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23 Oct 2018, 21:59
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
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Question Stats:
87% (00:45) correct
13%
(01:03)
wrong
based on 85
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In a certain class, x students are 10 years old, and the remaining y students are 11 years old. What is the average (arithmetic mean) age of all students in the class?
A. \(\frac{x+y}{21}\)
B. \(\frac{10x+11y}{21}\)
C. \(\frac{110xy}{x+y}\)
D. \(\frac{110xy}{xy}\)
E. \(\frac{10x+11y}{x+y}\)
A. \(\frac{x+y}{21}\)
B. \(\frac{10x+11y}{21}\)
C. \(\frac{110xy}{x+y}\)
D. \(\frac{110xy}{xy}\)
E. \(\frac{10x+11y}{x+y}\)
eswarchethu135
23 Oct 2018, 22:58
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Total number of students is x+y
No if students of 10 years old is x. So total age of x students is 10x
No if students of 11 years old is y. So total age of y students is 11y.
Now average is \(\frac{10x+11y}{x+y}\)
No if students of 10 years old is x. So total age of x students is 10x
No if students of 11 years old is y. So total age of y students is 11y.
Now average is \(\frac{10x+11y}{x+y}\)
23 Oct 2018, 23:21
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Bunuel
\(Average \ Age = \frac{Total \ Age \ of \ x \ students + Total \ Age \ of \ y \ students}{Total \ No \ of \ Students}\)
\(Average \ Age = \frac{10x + 11y}{(x + y )}\); Answer must be (E)
