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25 Oct 2018, 05:50
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
64% (02:19) correct
36%
(02:22)
wrong
based on 97
sessions
History
Date
Time
Result
Not Attempted Yet
A rectangular sheet of paper, when halved by folding it at the mid point of its longer side, results in
a rectangle, whose longer and shorter sides are in the same proportion as the longer and shorter
sides of the original rectangle. If the shorter side of the original rectangle is 2, what is the area of the
smaller rectangle?
a. \(4 \sqrt{2}\)
b. \(2 \sqrt{2}\)
c. \(\sqrt{2}\)
d. 1
e. 3
a rectangle, whose longer and shorter sides are in the same proportion as the longer and shorter
sides of the original rectangle. If the shorter side of the original rectangle is 2, what is the area of the
smaller rectangle?
a. \(4 \sqrt{2}\)
b. \(2 \sqrt{2}\)
c. \(\sqrt{2}\)
d. 1
e. 3
25 Oct 2018, 07:02
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RhythmGMAT
\(\frac{l}{b} = \frac{b}{(l/2)}\) where \(b = 2\) given
i.e. \(b^2 = l^2 / 2\)
i.e. \(l = 2√2\)
Area of smaller rectangle \(= (l/2)*b = (2√2/2)*2 = 2√2\)
Answer: Option B
25 Oct 2018, 08:05
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RhythmGMAT
OA: B
Initial Rectangle Dimensions
longer side \(= x\)
Shorter side\(= 2\)
Dimensions after folding
Longer side \(= 2\)
Shorter side \(= \frac{x}{2}\)
As per question
\(\frac{x}{2}=\frac{2}{\frac{x}{2}}\)
\(x^2=8 \quad;\quad x=2\sqrt{2}\)
Dimensions of Shorter Rectangle
Longer side \(= 2\)
Shorter side \(=\frac{2\sqrt{2}}{2}=\sqrt{2}\)
Area of Shorter Rectangle \(= 2\sqrt{2}\)
