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Bunuel
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Bunuel
If w + 2x = 150, 2w + 3y = 100, and x + 3z = 50, what is the value of w + x + y + z?

A. 12.5
B. 20
C. 50
D. 100
E. It cannot be determined from the information provided.


Sol:
Add all equations , you get 3x+3y+3z+3w= 300
therefore x+y+z+w=100
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1w + 2x + 0y + 0z = 150---------Eq 1
2w + 0x + 3y + 0z = 100---------Eq 2
0w + 1x + 0y + 3z = 50----------Eq 3

Now add all the three equations (Eq 1 + Eq 2 + Eq 3)

=> 3w + 3x + 3y + 3z = 300

Divide it by 3

=> w + x + y + z = 100

Answer IMO D
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Bunuel
If w + 2x = 150, 2w + 3y = 100, and x + 3z = 50, what is the value of w + x + y + z?

A. 12.5
B. 20
C. 50
D. 100
E. It cannot be determined from the information provided.

We can add the 3 equations together, and we have:

3w + 3x + 3y + 3z = 150 + 100 + 50

3w + 3x + 3y + 3z = 300

w + x + y + z = 100

Answer: D
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