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Bunuel
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NCRanjan
First Person has 8 options , 2nd has 7 options and so on
sp 8x7x6x5x4x3 = 20160

IMO E
Hi, the first person will not have 8 options but one(Since the chairs are not numbered and when that person does actually take the sseat, then and only then the numbering is done).
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Well i sure did not understand the 5! part but i did understand the following

First Of the insight that the first person will have 01 option helped me a lot so thanku

Starting with this

first person - 1 choice
second - 7
Third - 6

and so on
so 1 x7x6x5x4x3 = 2520 (the answer)
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The thought process matters a lot in this question. Your approach will change how you solve it.

One way is to think that 6 people are arranged in a circle = 5!
Now we need to place two chairs between these 6 people
This can be done in one of these two ways:
1. Both chairs between two individuals seated in a circle = 6C1
2. Or two chairs placed separately between these 6 seated individuals = 6C2

Hence the number of ways this can be done is = 5!(6C1 + 6C2) = 5! * 21 = 2520
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Bunuel
Six people are asked to sit down in a circle consisting of eight chairs.How many different ways are there to distribute the six people on the eight chairs?

A. 120
B. 720
C. 2,520
D. 5,040
E. 20,160
One interesting easy way to solve this could be -

Let's start with what we know - For n people to sit in a circle with n chairs, total number of combinations are (n-1)!

Now here, we see that we have 2 extra chairs. Let's suppose 2 identical holograms are going to occupy these chairs, then number of ways to arrange 8 people in a circle where 2 of them are identical can be,

7!/2! = 5040/2 = 2520

IMO: C
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