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hudacse6
any other explanation ?
Trying my bit

Median of the set of numbers - { 2, 3, 5, 7, 11, 12, and x. } must be 7

Now, try using the options -

(A) 2, 3, 5, 6 , 7, 11, 12 - Median = 6 ; If increased by 1 median increases by 1 , if decreased by 1 median decreases to 5
(B) 2, 3, 5, 7 , 7, 11, 12 - Median = 7 ; If increased by 1 median remains the same , if decreased by 1 median decreases to 6

Check with other options, only (B) works perfectly !!!
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Bunuel
A set of integers consists of 2, 3, 5, 7, 11, 12, and x. If x increases by 1, the median of the set stays unchanged. However, if x decreases by 1, the median of the set also decreases by 1. What is the value of x?

A. 6
B. 7
C. 8
D. 9
E. 10


Since, when x increases by 1, the median of the set stays unchanged and when x decreases by 1, the median of the set also decreases by 1, it must be true that x is the median or is very close to the median. So let’s say x is the median, and we have:

2, 3, 5, x, 7, 11, 12

We see that, in this case, x could be 5, 6, or 7. Since 5 is not in the choices, let’s start with x = 6.

If x = 6 (i.e., the original median is 6), then x + 1 = 7, and the list becomes:

2, 3, 5, 7, 7, 11, 12

However, the median is now 7. Therefore, x can’t be 6 since the median is supposed to stay unchanged.

If x = 7 (i.e., the original median is 7), then x + 1 = 8, and the list becomes:

2, 3, 5, 7, 8, 11, 12

We see that the median is still 7. Furthermore, x - 1 = 6, and the list becomes:

2, 3, 5, 6, 7, 11, 12

We see that the median is 6, which is 1 less than the original median. Therefore, x must be 7.

Answer: B
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only x=7 will fulfill the conditions mentioned in the question. as if x=7, then when x becomes 8 then also median does not change. when x becomes 6 the median becomes 6 instead of 7. Thus all conditions are fulfilled
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