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10 Dec 2018, 00:52
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B
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Question Stats:
89% (01:23) correct
11%
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based on 81
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In a regular n-sided polygon, the measure of a single angle is \(\frac{(n-2)*180}{n}\). The degree measure of an angle in a regular 10-sided polygon is how much greater than the degree measure of an angle in a regular 6-sided polygon?
A. 12
B. 24
C. 44
D. 120
E. 144
A. 12
B. 24
C. 44
D. 120
E. 144
Chethan92
Joined: 18 Jul 2018
Last visit: 21 Apr 2022
Posts: 899
Own Kudos:
Given Kudos: 95
Location: India
Concentration: Operations, General Management
Schools: IIMB EPGP'22 (M)
GMAT 1: 590 Q46 V25
GMAT 2: 690 Q49 V34
WE:Engineering (Energy)
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10 Dec 2018, 01:28
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10 sided polygon = (8*180)/10 = 144
6 sided polygon = (4*180)/6 = 120
Difference = 144-120 = 24
B is the answer.
6 sided polygon = (4*180)/6 = 120
Difference = 144-120 = 24
B is the answer.
10 Dec 2018, 04:07
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Bunuel
solve as per given relation given we get 144-120 = 24 IMO B
