Last visit was: 25 Apr 2026, 02:56 It is currently 25 Apr 2026, 02:56
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 25 Apr 2026
Posts: 109,822
Own Kudos:
Given Kudos: 105,878
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,822
Kudos: 811,134
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
PKN
Joined: 01 Oct 2017
Last visit: 11 Oct 2025
Posts: 809
Own Kudos:
Given Kudos: 41
Status:Learning stage
WE:Supply Chain Management (Energy)
Posts: 809
Kudos: 1,637
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
KanishkM
Joined: 09 Mar 2018
Last visit: 18 Dec 2021
Posts: 755
Own Kudos:
Given Kudos: 123
Location: India
Posts: 755
Kudos: 512
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
EgmatQuantExpert
User avatar
e-GMAT Representative
Joined: 04 Jan 2015
Last visit: 02 Apr 2024
Posts: 3,657
Own Kudos:
Given Kudos: 165
Expert
Expert reply
Posts: 3,657
Kudos: 20,881
Kudos
Add Kudos
Bookmarks
Bookmark this Post

Solution


Given:
    • A circular pond is bordered by a garden with a uniform width of 2
    • Area of pond = 81ᴨ

To find:
    • Area of the shaded region

Approach and Working:
    • Area of shaded region = area of bigger circle – area of pond

Radius of bigger circle = radius of pond + width of the garden
    • Radius of pond = √81 = 9
    • Thus, radius of bigger circle = 9 + 2 = 11

Therefore, area of shaded region = \(ᴨ(11^2 – 9^2) = 40ᴨ\)

Hence, the correct answer is Option D

Answer: D

User avatar
Archit3110
User avatar
Major Poster
Joined: 18 Aug 2017
Last visit: 25 Apr 2026
Posts: 8,630
Own Kudos:
Given Kudos: 243
Status:You learn more from failure than from success.
Location: India
Concentration: Sustainability, Marketing
GMAT Focus 1: 545 Q79 V79 DI73
GMAT Focus 2: 645 Q83 V82 DI81
GPA: 4
WE:Marketing (Energy)
Products:
GMAT Focus 2: 645 Q83 V82 DI81
Posts: 8,630
Kudos: 5,190
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

In the figure above, a circular pond is bordered by a garden with a uniform width of 2, represented by the shaded region. If the area of the circular pond is 81π, what is the area of the shaded region?

A 16π
B 20π
C 36π
D 40π
E 169π

Attachment:
2019-01-17_1528.png

area of pond = pi * r 2 = 81 pi ; r = 9
so garden + pond = 9+2 = 11 ; area = 121 pi
area of shaded region = 121pi -81pi = 40 pi
IMO D
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 24 Apr 2026
Posts: 22,286
Own Kudos:
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,286
Kudos: 26,534
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

In the figure above, a circular pond is bordered by a garden with a uniform width of 2, represented by the shaded region. If the area of the circular pond is 81π, what is the area of the shaded region?

A 16π
B 20π
C 36π
D 40π
E 169π

Attachment:
2019-01-17_1528.png

Since the area of the pond is 81π, the radius of the pond is 9, and thus the radius of the entire figure (pond plus garden) is 11.

Thus, the area of the shaded region is:

π(11^2) - π(9^2) = π(11^2 - 9^2) = π(121 - 81) = 40π

Answer: D
User avatar
Kinshook
User avatar
Major Poster
Joined: 03 Jun 2019
Last visit: 24 Apr 2026
Posts: 5,986
Own Kudos:
Given Kudos: 163
Location: India
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Products:
GMAT 1: 690 Q50 V34
Posts: 5,986
Kudos: 5,859
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

In the figure above, a circular pond is bordered by a garden with a uniform width of 2, represented by the shaded region. If the area of the circular pond is 81π, what is the area of the shaded region?

A 16π
B 20π
C 36π
D 40π
E 169π

Attachment:
2019-01-17_1528.png

Given:
1. In the figure above, a circular pond is bordered by a garden with a uniform width of 2, represented by the shaded region.
2. The area of the circular pond is 81π.

Asked: What is the area of the shaded region?

2. The area of the circular pond is 81π.
Radius of the circular pond is 9.

1. In the figure above, a circular pond is bordered by a garden with a uniform width of 2, represented by the shaded region.
Radius of pond + garden = 11

The area of the shaded region = \(\pi (R^2 - r^2) = \pi (11^2 - 9^2) = \pi (121 - 81) = 40\pi\)

IMO D
avatar
ragav182
Joined: 07 May 2016
Last visit: 24 May 2020
Posts: 9
Own Kudos:
Given Kudos: 29
Posts: 9
Kudos: 1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Directly jumping into the question tells me that to find out the area of the shaded region.

Area of the shaded region is given by = Outer circle - Inner Circle

Inner Circle Area is 81pi, we need to find out the outer circle radius. Thus, Outer Circle radius is Inner Circle radius + 2 (which is given in the question)

Inner Circle radius is 9 (the area is given as 81pi. So, the radius can be found by applying the Area of the Circle formula - pi(radius)^2)
So, Outer Circle radius is 9+2 = 11

Area of Shaded Region is 121pi-81pi = 40 pi

Ans: D
Moderators:
Math Expert
109822 posts
Tuck School Moderator
853 posts