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05 Feb 2019, 04:32
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
92% (01:06) correct
8%
(02:33)
wrong
based on 119
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Points A and B are separated by 50 miles on a straight road. Cyclist A leaves point A, heading toward point B, at a constant speed of 15 miles per hour. At the same time, cyclist B leaves point B, traveling toward point A, at a constant speed of 10 miles per hour. After how many minutes have elapsed will the two meet?
A. 115
B. 120
C. 125
D. 130
E. 135
A. 115
B. 120
C. 125
D. 130
E. 135
Archit3110
05 Feb 2019, 05:56
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Bunuel
relative speed = 15+10 = 25 mph
d= 50
t= 50/25 = 2 hrs = 2 * 60 = 120 mins
IMO B
General Discussion
06 Feb 2019, 19:44
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Bunuel
We can let the time traveled = n and create the distance equation:
15n + 10n = 50
25n = 50
n = 2 hours, which is 120 minutes
Answer: B
