Pierre sells lemonade for 2 dollars per glass. His costs include 5 lem

Question

Pierre sells lemonade for 2 dollars per glass. His costs include 5 lemons per glass at 25 cents per lemon, and 3 tablespoons of sugar per glass at 5 cents per tablespoon. If Pierre made at least 5 dollars in one day, and there were no other costs associated with making or selling the lemonade, how many glasses of lemonade could he have sold on that day?

I. 9
II. 10
III. 11

A. I only
B. I and II only
C. II and III only
D. I and III only
E. I, II, and III

I. 9
II. 10
III. 11

A. I only
B. I and II only
C. II and III only
D. I and III only
E. I, II, and III

Archit3110 · Answer

cost of lemonades 5*.25 ; 1.25
and sugar 3*.05 ;.15
total cost per glass = 1.4$
SP 2 $
proft ; 2-1.4 ; 0.6 $ 
he makes 5$ per day 
or say 5/.6 ; 8.33 glass ~ 9
so he needs to make at least 9 glasses to meet 5 $ in one day rate 
so Pierre could have made 9,10,11 glasses
IMO E

zlake23 · Answer

SP = 2
Cost = 1.40

1. 9 Glasses -- 18.00 - 12.60 = $5.40 (Yes)
2. 10 Glasses - 20.00 - 14.00 = $6.00 (Yes)
3. 11 Glasses - 22.00 - 15.40 = $6.60 (Yes)

Of course after we calculate the first statement there is no need to calculate the other 2.

IMO E.

alpacino · Answer

min profit = 5
Cost= (1/4)*5 + (1/20)*3=1.4$
Set up profit equation --> P*Q - C*Q = Profit
2Q - 1.4Q = 5
Q(0.6)=5 
Q= 5/(3/5) = 8.3 units required to make at least 5$ profit. 
Thus, I, II, III are correct. 
Go for (E)

SaquibHGMATWhiz · Answer

Solution:

CP per lemonade glass = cost of 5 lemons + cost of 3 tablespoons of sugar  = 5	imes 0.25 + 3	imes 0.05 = $1.4

SP per lemonade glass  = $2

Therefore, profit per lemonade glass  = SP - CP = 2 - 1.4 = $0.6

If we assume that Pierre sells  x  number of glasses each day, we can form an inequality  0.6x>5  
 ⇒x>\frac{5}{0.6} 
 ⇒x>8.33

Thus, the value of  x  can be 9, 10 and 11

Hence the right answer is    Option E

Pierre sells lemonade for 2 dollars per glass. His costs include 5 lem

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Pierre sells lemonade for 2 dollars per glass. His costs include 5 lem

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