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[GMAT math practice question]

Which of following satisfies the inequality \((2x-49)(x^2+6x+10) < 0\)?

\(A. 24\)
\(B. 25\)
\(C. 50\)
\(D. 51\)
\(E. 99\)

The two factors must have DIFFERENT SIGNS.
Each of the answer choices will yield a positive value for x² + 6x + 10.
Thus, the correct answer must yield a negative value for 2x-49.
Only A is viable:
(2*24) - 49 = -1

.
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=>

\(x^2+6x+10 = x^2+6x+9 + 1 = (x+3)^2+1 ≥ 1 > 0\).
Since \(x^2+6x+10 > 0\), we have \((2x-49)(x^2+6x+10) ≤ 0\), which implies that \(2x – 49 < 0\).
So, \(2x < 49\), and \(x < 24.5.\)

Therefore, the answer is A.
Answer: A
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Can we do this by using critical value?
-3 and 49/2 are two critical value.
Since, we are looking for negative value. Hence, any value between -3<x<49/2.

Which would mean 24.

Is this correct?

@brunnel?

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