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mangamma
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x cannot be 3, it needs to be between -1 and 1
chetan2u
mangamma
If 0 < x^y < 1, which of the following must be greater than x?

I. y^x
II. xy
III. 2x

A. None
B. I Only
C. III Only
D. I & III Only
E. II & III Only

X will be a fraction, and if you realize x can be both positive and negative, you can solve the question quite easily.

Say x=(3) and y=-1, so \(3^{-1}=\frac{1}{3}\)..
Option I... y^x =(-1)^3=-1, which is less than 3
Option II...xy =3*-1=-3, which is again less than X

Now say x =(-1/2) and y=2
Option III .... 2x=2*-1/2=-1, so less than x

Thus None, and answer is A
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pmahaja2
x cannot be 3, it needs to be between -1 and 1
chetan2u
mangamma
If 0 < x^y < 1, which of the following must be greater than x?

I. y^x
II. xy
III. 2x

A. None
B. I Only
C. III Only
D. I & III Only
E. II & III Only

X will be a fraction, and if you realize x can be both positive and negative, you can solve the question quite easily.

Say x=(3) and y=-1, so \(3^{-1}=\frac{1}{3}\)..
Option I... y^x =(-1)^3=-1, which is less than 3
Option II...xy =3*-1=-3, which is again less than X

Now say x =(-1/2) and y=2
Option III .... 2x=2*-1/2=-1, so less than x

Thus None, and answer is A

Check again. If x = 3 and y = -1, then x^y = 3^(-1) = 1/3, which is indeed greater than 0 and less than 1.
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