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Why is k=1 wrong?­

If k=1
x-6=x-2 becomes the simplified equation. This equation cannot have any solution either.
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If k = 1, then we get \(\frac{x-1}{x-2} = \frac{x-1}{x-6}\), which has a solution x = 1. You see we cannot reduce by x - 1 because we loos a root, specifically x - 1 = 0, which gives x = 1.
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is it correct to equate the coefficients s.t.
a1/a2=b1/b2!=c1/c2
=> this gives k = 5
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