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The time that any one person is inside the tunnel is equal to the time taken by the train to travel the length of the tunnel which is (5/30)=1/6 hour=10 minutes.....(i)
The time that all the persons in the train are inside the tunnel is equal to the time taken by the train to travel the length of the tunnel plus the time it takes to travel it's own length which is equal to 10+(0.5*60/30)=11 minutes.
Difference:11-10=1. Ans: A
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Relative distance covered by train in reference to a person standing outside the train= 500m
speed of train= 30kmph or 50/6 m/s
Time taken= 500/(50/6)=60 sec or 1 min
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A train 500 metres long is crossing a tunnel 5 kilometres long at a speed of 30 kilometres per hour. What is the difference in the time in minutes for which all the passengers of the train are inside the tunnel and the time for which a particular passenger is inside the tunnel?

A. 1
B. 1.5
C. 2
D. 3
E. 5

Difference = length of train / speed of train = 0.5/30 hours = 1 minute.

Option (A).
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Converting 30 km/hr to m/s = 30*5/18 = 25/3 m/s

500/(25/3) = 60s = 1 min

A
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­I made the question this way:

|-----|-------------------------------------------------------|
0    500                                                           5000

0 is where the singular individual starts, and it ends at 5000m (5km).

500 is where the train starts because it is the time when the entire train is inside the tunnel, and consequently, all the people are in it.

Time passenger = \(\frac{5(distance)}{30(speed)}\)
Time entire train = \(\frac{5-0.5}{30}\)

Difference = \(\frac{5}{30} - \frac{4.5}{30} = \frac{0.5}{30} = 1min\)­­
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But during exit as well we must add 500m just the. way we added during entry
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A train 500 metres long is crossing a tunnel 5 kilometres long at a speed of 30 kilometres per hour. What is the difference in the time in minutes for which all the passengers of the train are inside the tunnel and the time for which a particular passenger is inside the tunnel?

A. 1
B. 1.5
C. 2
D. 3
E. 5

A particular passenger is inside the tunnel for the time needed to cover 5 km:
5/30 hour = 10 minutes

All passengers are inside the tunnel only while the whole 500 m train fits completely inside the 5 km tunnel, so the relevant distance is:
5 - 0.5 = 4.5 km

Time = 4.5/30 hour = 9 minutes

Difference = 10 - 9 = 1 minute

Answer: A.

P.S. The wording is not perfect...

athakar7
But during exit as well we must add 500m just the. way we added during entry

No. That extra 500 m is added when you want the train to completely clear the tunnel. Here, the question asks for the time during which all passengers are inside the tunnel, and that starts when the last passenger enters and ends when the first passenger starts to exit, so the interval is tunnel length - train length, not tunnel length + train length.
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