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Cat food can =X

1/3(X)= morning
1/4(X)= evening

In a day 7/12(X)

Let X= 12

Roy opened 6 cans on Monday =6x=6*12=72

1 day =7

Mon to mon to Wed = 70

Thursday -only 2 , needed 5 more,

Thursday- answer

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Why isn't it Friday? There is still leftover, correct? The sum says " all of the food in the box".
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Consider 1 can has 12 parts, and cat eats 7 parts in a day out of 12, on Thursday it left with only 2 parts, so it emptied all cans on Thursday morning only ,

Please refer above solution.

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Bunuel
Roy's cat eats 1/3 of a can of cat food every morning and 1/4 of a can of cat food every evening. Before feeding his cat on Monday morning, Roy opened a box containing 6 cans of cat food. On what day of the week did the cat finish eating all the cat food in the box?


(A) Tuesday
(B) Wednesday
(C) Thursday
(D) Friday
(E) Saturday

Each day the cat eats 1/3 + 1/4 = 4/12 + 3/12 = 7/12 of a can of cat food. Therefore, 6 cans of cat food can last 6/(7/12) = 72/7 = 10 2/7. That is, a box of 6 cans of cat food can last a little more than 10 days. So the can would finish eating all the cat food in the box on the 11th day and 11 days counting from Monday is Thursday.

Answer: C
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