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m1033512
How is it 990 ?

Could someone help pls .

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GMAT TRICK- question says all the entries in which all three digits are not equal means 10 possibilities of three equal digits out of 10*10*10 =1000 are not to be taken.
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Bunuel
Entries in a particular lottery game are made up of three digits, each 0 through 9. If the order of digits in the entries matters, how many different possible entries exist in which all three digits are not equal?

A. 516
B. 720
C. 989
D. 990
E. 1321


all three digits order matter
so
10*9*8 ; 720
IMO B

Hi,

In your calculation, you are considering the digits can be used once. Question says you can use digits only all three should not be equal.

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ohkay ,

I missed to understand that the two same digits are allowed .

and the concept is to calculate all - number with 3 same digits

so it is 1000 - 10 = 990

understood

Thanks

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Bunuel
Entries in a particular lottery game are made up of three digits, each 0 through 9. If the order of digits in the entries matters, how many different possible entries exist in which all three digits are not equal?

A. 516
B. 720
C. 989
D. 990
E. 1321

Solution:

There are a total of 10 x 10 x 10 = 1000 entries of the lottery game, and only 10 of them have all three digits that are equal: 000, 111, 222, …, 999. Therefore, 1000 - 10 = 990 entries exist in which all three digits are not equal.

Answer: D
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Identify that there are 10 ways for each digit, so we have 10 * 10 * 10 = 1000. Only 10 possible numbers have all digits the same (111, 222, 333, 444, 555, 666, 777, 888, 999, and 000). Thus, we do 1000 - 10 = 990 to get to our answer.
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