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01 May 2019, 00:47
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
89% (01:23) correct
11%
(00:50)
wrong
based on 72
sessions
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Not Attempted Yet
The fraction \(\frac{11!}{77}\) is equivalent to which of the following?
A. \(2^73^35^2\)
B. \(2^93^45^2\)
C. \(2^83^45^2\)
D. \(2^83^45^27^2\)
E. \(2^83^45^211\)
A. \(2^73^35^2\)
B. \(2^93^45^2\)
C. \(2^83^45^2\)
D. \(2^83^45^27^2\)
E. \(2^83^45^211\)
eswarchethu135
01 May 2019, 00:57
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\(\frac{1*2*3*4*5*6*7*8*9*10*11}{77}\)
\(2*3*(2)^2*5*3*2*(2)^3*(3)^2*2*5\)
\(2^8*3^4*5^2\)
OPTION: C
\(2*3*(2)^2*5*3*2*(2)^3*(3)^2*2*5\)
\(2^8*3^4*5^2\)
OPTION: C
01 May 2019, 01:00
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Start by eliminating options D and E. 11! Would have only one 7 and one 11, since we are dividing it by 77 these factors should be removed.
In the remaining case we are left with 5^2 , a 5 each from 5 and 10
Number of 3's in 11! Would be from 3,6,9(9 is 3^2) so total power of 3 is 4
Number of 2's in 11! Would be from 2,4,6,8,10(4 is 2^2 and 8 is 2^3) so total power of 2 is 8
IMO C
Posted from my mobile device
In the remaining case we are left with 5^2 , a 5 each from 5 and 10
Number of 3's in 11! Would be from 3,6,9(9 is 3^2) so total power of 3 is 4
Number of 2's in 11! Would be from 2,4,6,8,10(4 is 2^2 and 8 is 2^3) so total power of 2 is 8
IMO C
Posted from my mobile device
