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06 May 2019, 21:11
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
81% (01:47) correct
19%
(02:01)
wrong
based on 165
sessions
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Fred and Bobbie are book collectors, and Fred has twice as many books as Bobbie does. One-fourth of Fred’s books are signed by the authors, and three-fifths of Bobbie’s books are signed by the authors. If Fred and Bobbie combine their collections, what fraction of the books are signed by the authors?
A. 11/30
B. 29/60
C. 23/30
D. 17/20
E. It cannot be determined.
A. 11/30
B. 29/60
C. 23/30
D. 17/20
E. It cannot be determined.
06 May 2019, 22:41
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Bunuel
Given F:B = 2:1
let F has 2x books and B has 1x books ; Total they have 3x books
now,
Fred Signed books = \(\frac{2x}{4}\) = \(\frac{x}{2}\)
Bobbies Signed books = \(\frac{3x}{5}\)
We are asked to find : \(\frac{(#Fred signed books + #Bobbies signed books)}{#Total books}\)
we have : ((x/2)+(3x/5))/3x
Solving we get Ans A) \(\frac{11}{30}\)
06 May 2019, 23:31
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let's assume that Bobbie has 10 books.
Then Fred has 2×10=20 books
1/5×20=5
and 3/5×10 =6
combine Fraction =books signed by author/initial no.of books
=11/30
Posted from my mobile device
Then Fred has 2×10=20 books
1/5×20=5
and 3/5×10 =6
combine Fraction =books signed by author/initial no.of books
=11/30
Posted from my mobile device
