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Should it not be solved by Pythagoras theorem? How to approach it?
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Slope of the diagonal of the bottom left corner tile wrt left length is not same as that of the diagonal of the floor. So either you can use the approach i mentioned earlier or you can use the following approach.

Number of the bug visit= 10+17- HCF(10,17)=27-1=26.


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Should it not be solved by Pythagoras theorem? How to approach it?
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Bunuel
A rectangular floor that is 10 feet wide and 17 feet long is tiled with 170 one-foot square tiles. A bug walks from one corner to the opposite corner in a straight line. Including the first and the last tile, how many tiles does the bug visit?

A. 17
B. 25
C. 26
D. 27
E. 28


The easiest way to solve this problem is to visualize this problem.
Attachment:
Solution.JPG
Solution.JPG [ 65.13 KiB | Viewed 8602 times ]

Therefore, the minimum tiles that the bug visits while moving from one corner of the rectangular floor is 26(Option C)

P.S For the right angled triangle formed - the hypotenuse will be the shortest distance and the length of the hypotenuse is around 20.
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Bunuel
A rectangular floor that is 10 feet wide and 17 feet long is tiled with 170 one-foot square tiles. A bug walks from one corner to the opposite corner in a straight line. Including the first and the last tile, how many tiles does the bug visit?

A. 17
B. 25
C. 26
D. 27
E. 28

Bunuel VeritasKarishma, solution please?
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Bunuel
A rectangular floor that is 10 feet wide and 17 feet long is tiled with 170 one-foot square tiles. A bug walks from one corner to the opposite corner in a straight line. Including the first and the last tile, how many tiles does the bug visit?

A. 17
B. 25
C. 26
D. 27
E. 28


The number of square tiles visited will be 17 + 9 = 26

Attachment:
Screenshot 2019-06-10 at 13.29.58.png
Screenshot 2019-06-10 at 13.29.58.png [ 20.08 KiB | Viewed 7862 times ]

The logic is this: From A to C, the ant will cover 17 tiles.
But from A to D, the ant will cover 17 + 2 = 19 tiles. Since there are three rows, every time the ant crosses from one row to another row, it crosses two tiles (shown by the coloured tiles). So for every extra row, it covers one extra tile.

Since we have to cover 10 rows, the number of tiles crossed will be 17 + 9 = 26
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