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nick1816
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Find the square of the length of the shortest path that can be drawn 18 May 2019, 02:24
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95% (hard)

Question Stats:

19% (03:10) correct 81% (02:46) wrong based on 47 sessions

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Find the square of the length of the shortest path that can be drawn from the point (6,3) to the point (2,8) such that the path touches the x-axis and the y-axis once.

A. 41
B. 100
C. 149
D. 185
E. 196
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D

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ManjariMishra
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Find the square of the length of the shortest path that can be drawn 20 May 2019, 06:40
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Can anybody please explain the solution

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Find the square of the length of the shortest path that can be drawn 20 May 2019, 06:51
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The shortest path between 2 points in 2-Dimension is always a straight line. The reflected part is equal to the distance between (6,3) and (-2,-8)
Square of distance= (6-(-2))^2+(3-(-8))^2= 8^2+11^2=185
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Can anybody please explain the solution

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fogarasm
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Find the square of the length of the shortest path that can be drawn 25 May 2019, 06:25
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nick1816
The shortest path between 2 points in 2-Dimension is always a straight line. The reflected part is equal to the distance between (6,3) and (-2,-8)
Square of distance= (6-(-2))^2+(3-(-8))^2= 8^2+11^2=185
ManjariMishra
Can anybody please explain the solution

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nick1816 - I don't fully understand. How do we know the distance between (6,3) and (-2,-8) is the same as the reflected portion? Thanks in advance.
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Find the square of the length of the shortest path that can be drawn Updated on: 26 May 2019, 13:16
Originally posted by nick1816 on 25 May 2019, 08:39.
Last edited by nick1816 on 26 May 2019, 13:16, edited 1 time in total.
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The shortest path between 2 points in 2-Dimension is always a straight line
1. The shortest vertical distance between point A and B,if the path have to touch x axis, is equal to |0-3|+|8-0|=11
2. The shortest horizontal distance between point A and B,if the path have to touch y axis, is equal to |0-6|+|2-0|=8

Square of shortest distance= 11^2 + 8^2= 185


fogarasm
nick1816
The shortest path between 2 points in 2-Dimension is always a straight line. The reflected part is equal to the distance between (6,3) and (-2,-8)
Square of distance= (6-(-2))^2+(3-(-8))^2= 8^2+11^2=185
ManjariMishra
Can anybody please explain the solution

Posted from my mobile device

nick1816 - I don't fully understand. How do we know the distance between (6,3) and (-2,-8) is the same as the reflected portion? Thanks in advance.
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Find the square of the length of the shortest path that can be drawn 25 May 2019, 09:24
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Bunuel could you please help in this question ?
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Find the square of the length of the shortest path that can be drawn 07 Mar 2025, 22:34
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