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21 May 2019, 00:21
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (01:24) correct
12%
(01:26)
wrong
based on 82
sessions
History
Date
Time
Result
Not Attempted Yet
At a certain fruit stand, the price of an apple is twice the price of an orange. For which of the following combinations of apples and oranges is the total price equal to the total price of 20 oranges?
I. 2 apples and 16 oranges
II. 3 apples and 14 oranges
III. 6 apples and 8 oranges
A. I only
B. II only
C. III only
D. I and II only
E. I, II and III
I. 2 apples and 16 oranges
II. 3 apples and 14 oranges
III. 6 apples and 8 oranges
A. I only
B. II only
C. III only
D. I and II only
E. I, II and III
21 May 2019, 02:48
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Bunuel
let orange = 2
and apple = 4
so 20 * 2; 40
we see that for all give options we get 40
IMO E
22 May 2019, 05:24
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Bunuel
Let the price of an orange = x
Then, price of an apple = 2x
Price of 20 oranges = 20x
Case 1 : 2 apples and 16 oranges
Price of 2 apples = 2*2x <------> Price of 16 oranges = 16x
2*2x + 16x = 20x
20x = 20x ----------- Valid
Case 2 : 3 apples and 14 oranges
Price of 3 apples = 3*2x <------> Price of 14 oranges = 14x
3*2x + 14x = 20x
20x = 20x ----------- Valid
Case 3 : 6 apples and 8 oranges
Price of 6 apples = 6*2x <------> Price of 8 oranges = 8x
6*2x + 8x = 20x
20x = 20x ----------- Valid
Hence E
