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There are couple of ways to solve this question, but this one is a bit shorter and trickier than others. This one uses basic concept of factorization tho.
ayushkumar22941
tough problem , you cant solve such question unless you have practiced such questions.
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Let k be the common odd factor.
Thus, x+5 = km for some integer m
x = km-5
\(x^2+9 = (km-5)^2 + 9 = (km)^2 - 10km + 25 +9 = (km)^2 - 10km + 34\)
Hence k must be an odd factor of 34 => k=17
x = 12, 29, 46, 63, 80 or 97 (= 17q + 12, where q is a nonnegative integer)

Option C
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