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Bunuel
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Two cars started from the same point and traveled on a straight course 27 May 2019, 01:29
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Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart. If one car traveled, on average, 8 miles per hour faster than the other car, what was the average speed of faster car for the 2-hour trip?

A. 32 mph
B. 40 mph
C. 48 mph
D. 56 mph
E. 64 mph
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D
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Two cars started from the same point and traveled on a straight course 27 May 2019, 01:40
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Bunuel
Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart. If one car traveled, on average, 8 miles per hour faster than the other car, what was the average speed of faster car for the 2-hour trip?

A. 32 mph
B. 40 mph
C. 48 mph
D. 56 mph
E. 64 mph
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Let the speeds of 2 cars be v mph and v+8 mph.

Distance traveled by these cars in 2 hours is 2v and 2(v+8)

So, 2v + 2(v+8) = 208
4v = 208 - 16 = 192
v = 48 mph

Avg Speed of fast car = v + 8 = 56 mph

Option D
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Two cars started from the same point and traveled on a straight course 27 May 2019, 02:07
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2v+2(v+8) = 208
4v +16 =208
4v = 192
v = 48

And v+8 = 56i have solved it like this but have a query will the average will not remain same for both the cars.isnt it the speed that we have calculated.Can you please guide Bunuel

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Two cars started from the same point and traveled on a straight course 27 May 2019, 05:09
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Bunuel
Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart. If one car traveled, on average, 8 miles per hour faster than the other car, what was the average speed of faster car for the 2-hour trip?

A. 32 mph
B. 40 mph
C. 48 mph
D. 56 mph
E. 64 mph
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speed of A = x
speed of B = x+8
distance travelled in 2 hrs
2x+2x+16=208
4x=192
x=48
speed of B; 48+8;56
IMO D
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Two cars started from the same point and traveled on a straight course 25 Oct 2020, 04:27
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CAR 2................................O......................................CAR 1
<....................................208....................................>
D 208 - D
S1 S2=S1+8



S2 = S1+8
(208 - D)/2 = D/2 + 8
=> (208 - D)/2 - D/2 = 8
=> (208 - 2D)/2 = 8
=> 208 - 2D = 16
=>2D = 192
=> D = 96

S1= 96/2 = 48 MILE/HOUR
S2 = 56 MILE/HOUR
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Two cars started from the same point and traveled on a straight course 24 Nov 2020, 13:51
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Bunuel
Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart. If one car traveled, on average, 8 miles per hour faster than the other car, what was the average speed of faster car for the 2-hour trip?

A. 32 mph
B. 40 mph
C. 48 mph
D. 56 mph
E. 64 mph
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Let the speed of one car is \(s\) miles per hour

So, the speed of the faster car is \(s+8\)

\(2s+2(s+8)=208\)

\(2s+2s+16=208\)

\(4s=192\)

\(s=48\)

The speed of the faster car is \(48+8=56\)

The answer is D
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Two cars started from the same point and traveled on a straight course 30 Nov 2020, 11:37
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Bunuel
Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart. If one car traveled, on average, 8 miles per hour faster than the other car, what was the average speed of faster car for the 2-hour trip?

A. 32 mph
B. 40 mph
C. 48 mph
D. 56 mph
E. 64 mph
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Solution:

We can let x = the average speed, in mph, of the faster car. Thus, x - 8 = the average speed of the slower car, and we can create the equation:

2(x + x - 8) = 208

2x - 8 = 104

2x = 112

x = 56

Answer: D
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Two cars started from the same point and traveled on a straight course 30 Nov 2020, 12:49
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Given
    • Two cars started from the same point and traveled on a straight course in opposite directions for exactly 2 hours, at which time they were 208 miles apart.
    • One car traveled, on average, 8 miles per hour faster than the other car.


To Find

    • The average speed of the faster car for the 2-hour trip.

Approach and Working Out


    • Faster car speed = x mph, slower car = (x – 8) mph.

    • 2(x + x – 8) = 208
      o 4x = 208 + 16
      o 4x = 224
      o x = 56

Correct Answer: Option D
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Two cars started from the same point and traveled on a straight course 02 Jul 2024, 07:08
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