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Difficulty:
35%
(medium)
Question Stats:
75% (02:08) correct
25%
(02:36)
wrong
based on 178
sessions
History
Date
Time
Result
Not Attempted Yet
A person who has a certain amount with him goes to market. He can buy 50 oranges or 40 mangoes. He retains 10% of the amount for taxi fares and buys 20 mangoes and of the balance he purchases oranges. Number of oranges he can purchase is
A. 10
B. 15
C. 20
D. 25
E. 30
A. 10
B. 15
C. 20
D. 25
E. 30
Posts: 34
Suppose he has 100 rs with him.
HE can buy 40 mangoes - so 2.5 rs/mangos
"" "" " 50 oranges - so 2 rs /orange
he keeps 10% aside, so 10 rs has been kept aside.
now he buys 20 mangoes - so he spends 50 rs on mangoes.
remaining = 100-10-50 = 40. He can buy 20 oranges in with this amount.
Option C
HE can buy 40 mangoes - so 2.5 rs/mangos
"" "" " 50 oranges - so 2 rs /orange
he keeps 10% aside, so 10 rs has been kept aside.
now he buys 20 mangoes - so he spends 50 rs on mangoes.
remaining = 100-10-50 = 40. He can buy 20 oranges in with this amount.
Option C
General Discussion
Posts: 477
Deconstructing the Question
Let total money be M.
He can buy:
50 oranges ⇒ price per orange = \(\frac{M}{50}\)
40 mangoes ⇒ price per mango = \(\frac{M}{40}\)
He keeps 10% for taxi, so money available:
\(0.9M\)
Step-by-step
Cost of 20 mangoes:
\(20 \times \frac{M}{40} = \frac{M}{2}\)
Remaining money:
\(0.9M - 0.5M = 0.4M\)
Number of oranges he can buy:
\(\frac{0.4M}{M/50}\)
\(= 0.4M \times \frac{50}{M}\)
\(= 0.4 \times 50 = 20\)
Answer: C
Let total money be M.
He can buy:
50 oranges ⇒ price per orange = \(\frac{M}{50}\)
40 mangoes ⇒ price per mango = \(\frac{M}{40}\)
He keeps 10% for taxi, so money available:
\(0.9M\)
Step-by-step
Cost of 20 mangoes:
\(20 \times \frac{M}{40} = \frac{M}{2}\)
Remaining money:
\(0.9M - 0.5M = 0.4M\)
Number of oranges he can buy:
\(\frac{0.4M}{M/50}\)
\(= 0.4M \times \frac{50}{M}\)
\(= 0.4 \times 50 = 20\)
Answer: C
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