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03 Jun 2019, 01:43
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
91% (00:53) correct
9%
(01:05)
wrong
based on 44
sessions
History
Date
Time
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Not Attempted Yet
The average (arithmetic mean) of 8 numbers is 42. One of the numbers is removed from the set, and the resulting average (arithmetic mean) of the remaining numbers is 40. What number was removed from the set?
(A) 26
(B) 28
(C) 50
(D) 54
(E) 56
(A) 26
(B) 28
(C) 50
(D) 54
(E) 56
Mo2men
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03 Jun 2019, 01:51
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Bunuel
sum of 8 numbers = 8*42
sum of 7 numbers = 7*40
Subtract. (you do not need to perform the multiplication at all.
8*42 - 7*40 = 8*7*6 - 7*8*5 = 7*8(6-5) = 56
Answer: E
03 Jun 2019, 01:51
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If x=sum of 8 numbers, then \(\frac{x}{8}\)=42 x=336
If y=sum of 7 numbers (after removing 1 number from the set) then \(\frac{y}{7}\)=40 y=280
The difference between x and y is the number which we have removed
336-280=56
IMO
Ans: E
If y=sum of 7 numbers (after removing 1 number from the set) then \(\frac{y}{7}\)=40 y=280
The difference between x and y is the number which we have removed
336-280=56
IMO
Ans: E
