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10 Jun 2019, 00:15
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[GMAT math practice question]
A \(30^o-60^o-90^o\) triangle is drawn on the exterior of equilateral triangle ABC as shown in the figure below so that the hypotenuse of the right triangle forms one side of the equilateral triangle. If the length of CD is \(2\), what is the length of AD?
6.10.png [ 5.76 KiB | Viewed 3300 times ]
A. 3
B. 4
C. 5
D. √7
E. 2√7
A \(30^o-60^o-90^o\) triangle is drawn on the exterior of equilateral triangle ABC as shown in the figure below so that the hypotenuse of the right triangle forms one side of the equilateral triangle. If the length of CD is \(2\), what is the length of AD?
Attachment:
6.10.png [ 5.76 KiB | Viewed 3300 times ]
A. 3
B. 4
C. 5
D. √7
E. 2√7
AbbasAli12
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10 Jun 2019, 00:46
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Cos 60 = CD/CB. From here you can get CB. Now CB = AB = AC. You can also find BD using Pythagoras theorem and similarly you can find the length of AD because triangle ADB is right angled triangle.
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sakshamchhabra
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10 Jun 2019, 01:19
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since this is a 30-60-90 triangle so we can figure out, BD and BC
triangle ABC is equilateral so, BC=AB,
Triangle ABD is a right triangle so we can find AD.
triangle ABC is equilateral so, BC=AB,
Triangle ABD is a right triangle so we can find AD.
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IMG_20190610_134502.jpg [ 1.97 MiB | Viewed 3248 times ]
