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Bunuel
If a point is arbitrarily selected inside a circle of radius R, what is the probability that the distance from this point to the center of the circle will be greater than R/2 ?

A. 1/2
B. 3/4
C. 7/8
D. 1/4*R^2
E. 3/4*R^2

[πR^2 - π(R/2)^2]/(πR^2)

[πR^2 - πR^2/4]/(πR^2)

[3πR^2/4]/(πR^2)

3/4

Alternate Solution:

Let’s assume that the radius of the circle is 2. This problem can be approached by considering the entire circle (with area of 4π) and then drawing a concentric circle whose radius is half that of the bigger circle (so radius = 1). The area of this smaller circle is π. Any point inside this smaller circle will be less than 1 unit from the center of the circle, and the probability of a point being in this smaller circle will be π/4π = 1/4. Thus, any point outside the smaller circle (but inside the larger circle) will satisfy the requirement of being more than 1 unit from the center of the circle, and its probability will be 1 - ¼ = ¾.

Answer: B
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Hey Bunuel firas92 chetan2u KarishmaB gmatophobia,

My doubt might seem basic,

My thought process was the same at arriving soln. but I got 1/4 as the answer, can you help identify my flaw?

= pi.r^2 - pi.(r/2)^2
= pi (r - (r/2))^2
= pi (r/2)^2

Hence,1/4 was my answer.

firas92
Any point within the yellow region shown below will be at a distance greater than R/2 from the centre.

Therefore the question basically asks, what is the probability that the selected point lies within the yellow region.

\(Probability = \frac{Required Area}{Total Area}\)

Probability = π(R^2-(R/2)^2)/π*R^2 = 1-(1/4)/1 = 3/4

Answer is (B)
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a^2 - b^2 = (a-b)(a+b)
(a-b)^2 = (a-b)(a-b)

It is clear that both the expressions on the left mentioned above are not equal.

Hence, r^2 - (r/2)^2 is not same as (r-r/2)^2.

Sujithz001
Hey Bunuel firas92 chetan2u KarishmaB gmatophobia,

My doubt might seem basic,

My thought process was the same at arriving soln. but I got 1/4 as the answer, can you help identify my flaw?

= pi.r^2 - pi.(r/2)^2
= pi (r - (r/2))^2
= pi (r/2)^2

Hence,1/4 was my answer.

firas92
Any point within the yellow region shown below will be at a distance greater than R/2 from the centre.

Therefore the question basically asks, what is the probability that the selected point lies within the yellow region.

\(Probability = \frac{Required Area}{Total Area}\)

Probability = π(R^2-(R/2)^2)/π*R^2 = 1-(1/4)/1 = 3/4

Answer is (B)
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is this q relevant from gmat focus pespective Bunuel?
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Bunuel
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ananya88888888888
is this q relevant from gmat focus pespective Bunuel?

If the formula for the area of a circle is not given, then this question is not very likely to appear on the current GMAT.

If the formula is provided in the question, however, then this type of probability question could still be relevant.
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