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Bunuel
If set Q consists of all three digit numbers divisible by 4, what is the mean of the set?

(A) 498
(B) 499.5
(C) 548
(D) 549.5
(E) 550

total terms of 3 digit no divisible by 4 ; 100 to 996 ; 996-100 +1 ; 225
and sum of these 225 terms ;
sn=225/2* ( 2*225+(224*4) = 548*225
sum / total terms = mean ;; 548*225/225 = 548
IMO C
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I did it this way.... since all numbers in the set are divisible by 4, mean should also be divisible by 4. Only 548 is divisible by 4 among all the options. Can anybody tell me if my approach is right or not?
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Bunuel
If set Q consists of all three digit numbers divisible by 4, what is the mean of the set?

(A) 498
(B) 499.5
(C) 548
(D) 549.5
(E) 550


Can we directly select option C as the answer because it is the only option perfectly divisible by 4 (as all 3 digits are divisible by 4 there mean should also be divisible by 4) ?
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moropa2018
I did it this way.... since all numbers in the set are divisible by 4, mean should also be divisible by 4. Only 548 is divisible by 4 among all the options. Can anybody tell me if my approach is right or not?
Hi! I did the same thing, but don't know if it is the correct approach, could be not because in the formulas the number has to be divisible by 2, but nothing is said about 4. maybe someone can help
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