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prashantbacchewar
What is probablity that the sum of two dice will yield 4 ot 6

With two dice, enumeration is quite simple

4 = {1 3,2 2, 3 1} = 3 cases
5 = {1 4,2 3,3 2, 4 1} = 4 cases
6 = {1 5,2 4,3 3,4 2,5 1} = 5 cases

So probability is 12/36 or 1/3

One thing you can note for two dice (not really useful in this particular question) is that the most probable outcome is 7. And that the distribution of outcomes is symmetric about 7. So Prob(7+x)=Prob(7-x).

Why did you calculate 5 = {1 4,2 3,3 2, 4 1} = 4 cases? The question asks for 4 OR 6, not from 4 to 6. Please correct me if I'm wrong. Thanks
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prashantbacchewar
What is probability that the sum of two dice will yield 4 or 6?

There are a total of 6 x 6 = 36 outcomes.

The outcomes that sum to 4 are:

1,3

3,1

2,2

So the probability of getting a sum of 4 is 3/36.

The outcomes that sum to 6 are:

1,5

5,1

2,4

4,2

3,3

So the probability of getting a sum of 6 is 5/36.

Thus, the probability of the dice summing to either 4 or 6 is 3/36 + 5/36 = 8/36 = 2/9.
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What is the probability that the sum of two dice rolls will yield a 4 OR 6?

A. 1/9
B. 2/9
C. 1/3
D. 4/9
E. 7/9
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Bunuel
What is the probability that the sum of two dice rolls will yield a 4 OR 6?

A. 1/9
B. 2/9
C. 1/3
D. 4/9
E. 7/9

# of cases with sum yielding 4 = 13, 31, 22 = 3 cases
# of cases with sum yielding 6 = 15, 51, 24, 42, 33 = 5 cases
# of favorable outcomes = 8
# of total outcomes = 6*6 = 36

Probability = 8/36 = 2/9

IMO B
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Bunuel
What is the probability that the sum of two dice rolls will yield a 4 OR 6?

A. 1/9
B. 2/9
C. 1/3
D. 4/9
E. 7/9

# of cases with sum yielding 4 = 13, 31, 22 = 3 cases
# of cases with sum yielding 6 = 15, 51, 24, 42, 33 = 5 cases
# of favorable outcomes = 8
# of total outcomes = 6*6 = 36

Probability = 8/36 = 2/9

IMO B

Why does order matter in this case?
I remember solving one similar question in which order was not taken into consideration.

Thanks in advance.
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Bunuel
What is the probability that the sum of two dice rolls will yield a 4 OR 6?

A. 1/9
B. 2/9
C. 1/3
D. 4/9
E. 7/9

Possibilities of Sum 6 and 4 = 33,42,24,15,51 and 22,13,31.
Total Possibilities - 6*6= 36
Probab. = 8/36=2/9 IMO B
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Bunuel
What is the probability that the sum of two dice rolls will yield a 4 OR 6?

A. 1/9
B. 2/9
C. 1/3
D. 4/9
E. 7/9

sum 4; 1,3 ; 2,2 ; 3,1
sum 6; 1,5 ; 2,4 ; 3,3; 4,2 ; 5,1
total possiblitiesl 36
and possible pairs; 8
8/36 ; 2/9
IMO B
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Bunuel
What is the probability that the sum of two dice rolls will yield a 4 OR 6?

A. 1/9
B. 2/9
C. 1/3
D. 4/9
E. 7/9

Total outcomes = 36
Favourable for sum 4 = (1,3), (2,2), (3,1) = 3
Favourable for sum 6 = (1,5), (2,4), (3,3), (4,2), (5,1) = 5

Probability of sum 4 OR 6 = 3/36 + 5/36
= 8/36
= 2/9

IMO Option B

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3/36 + 5/36 = 2/9

Answer B
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↧↧↧ Detailed Video Solution to the Problem ↧↧↧


We need to find What is the probability that the sum of two dice will yield a 4 or a 6?


As we are rolling two dice => Number of cases = \(6^2\) = 36

Now for the sum to be 4 or 6 we need to find out what comes in both the dice roll. Following outcomes will yield 4 or 6 as the sum
(1,3), (1,5), (2,2), (2,4), (3,1), (3,3), (4,2), (5,1) = 8 outcomes

=> Probability that the sum of two dice will yield a 4 or a 6 = \(\frac{8}{36}\) = \(\frac{2}{9}\)

So, Answer will be \(\frac{2}{9}\)
Hope it helps!

Watch the following video to learn How to Solve Dice Rolling Probability Problems

­
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↧↧↧ Detailed Video Solution to the Problem ↧↧↧



We need to find What is the probability that the sum of two dice will yield a 4 or a 6?

As we are rolling two dice => Number of cases = \(6^2\) = 36

Now for the sum to be 4 or 6 we need to find out what comes in both the dice roll. Following outcomes will yield 4 or 6 as the sum
(1,3), (1,5), (2,2), (2,4), (3,1), (3,3), (4,2), (5,1) = 8 outcomes

=> Probability that the sum of two dice will yield a 4 or a 6 = \(\frac{8}{36}\) = \(\frac{2}{9}\)

So, Answer will be B
Hope it helps!

Playlist on Solved Problems on Probability here

Watch the following video to MASTER Dice Rolling Probability Problems

­
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