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Bunuel
What is the probability that the sum of two dice rolls will yield a 4 OR 6?

A. 1/9
B. 2/9
C. 1/3
D. 4/9
E. 7/9

Possibilities of Sum 6 and 4 = 33,42,24,15,51 and 22,13,31.
Total Possibilities - 6*6= 36
Probab. = 8/36=2/9 IMO B
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Bunuel
What is the probability that the sum of two dice rolls will yield a 4 OR 6?

A. 1/9
B. 2/9
C. 1/3
D. 4/9
E. 7/9

sum 4; 1,3 ; 2,2 ; 3,1
sum 6; 1,5 ; 2,4 ; 3,3; 4,2 ; 5,1
total possiblitiesl 36
and possible pairs; 8
8/36 ; 2/9
IMO B
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Bunuel
What is the probability that the sum of two dice rolls will yield a 4 OR 6?

A. 1/9
B. 2/9
C. 1/3
D. 4/9
E. 7/9

Total outcomes = 36
Favourable for sum 4 = (1,3), (2,2), (3,1) = 3
Favourable for sum 6 = (1,5), (2,4), (3,3), (4,2), (5,1) = 5

Probability of sum 4 OR 6 = 3/36 + 5/36
= 8/36
= 2/9

IMO Option B

Pls Hit kudos if you like the solution

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3/36 + 5/36 = 2/9

Answer B
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↧↧↧ Detailed Video Solution to the Problem ↧↧↧



We need to find What is the probability that the sum of two dice will yield a 4 or a 6?

As we are rolling two dice => Number of cases = \(6^2\) = 36

Now for the sum to be 4 or 6 we need to find out what comes in both the dice roll. Following outcomes will yield 4 or 6 as the sum
(1,3), (1,5), (2,2), (2,4), (3,1), (3,3), (4,2), (5,1) = 8 outcomes

=> Probability that the sum of two dice will yield a 4 or a 6 = \(\frac{8}{36}\) = \(\frac{2}{9}\)

So, Answer will be B
Hope it helps!

Watch the following video to learn How to Solve Dice Rolling Probability Problems

­
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