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GOHOSATRAJIT
A boat traveled 90 miles upstream at a constant speed and then traveled the same distance downstream at a constant speed. If the constant velocity of the water is 3 miles per hour and the whole trip took 12.5 hours, the upstream trip took hour many more hours than the downstream trip?

(A) 1
(B) 1.5
(C) 2
(D) 2.5
(E) 3

We can let the speed of the boat in still water be r and create the equation:

90/(r - 3) + 90/(r + 3) = 12.5

Multiplying the equation by (r -3)(r + 3), or r^2 - 9, we have:

90(r + 3) + 90(r - 3) = 12.5(r^2 - 9)

90r + 270 + 90r - 270 = 12.5r^2 - 112.5

180r = 12.5r^2 - 112.5

Multiplying by 2, we have:

360r = 25r^2 - 225

Dividing by 5, we have:

5^2 - 72r - 45 = 0

(5r + 3)(r - 15) = 0

r = -3/5 or r = 15

Since r can’t be negative, r = 15. Therefore, it takes the boat 90/(15 - 3) = 90/12 = 7.5 hours to travel upstream and 90/(15 + 3) = 90/18 = 5 hours to travel downstream. So it takes 7.5 - 5 = 2.5 more hours to travel upstream than downstream.

Answer: D

How did you assume the boat's speed upstream and downstream is constant? Surely if this was the case the question would've said "at the same constant speed"..
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GOHOSATRAJIT
A boat traveled 90 miles upstream at a constant speed and then traveled the same distance downstream at a constant speed. If the constant velocity of the water is 3 miles per hour and the whole trip took 12.5 hours, the upstream trip took hour many more hours than the downstream trip?

(A) 1
(B) 1.5
(C) 2
(D) 2.5
(E) 3

Given:
1. A boat traveled 90 miles upstream at a constant speed and then traveled the same distance downstream at a constant speed.
2. The constant velocity of the water is 3 miles per hour.
3. The whole trip took 12.5 hours.

Asked: Upstream trip took hour many more hours than the downstream trip?

Let the speed on the boat be v kmh

90/(v-3) + 90/(v+3) = 12.5
v = 15 kmh
I got the solution by hit and try but this can be solved using quadratic equations.
90/12 + 90/18 = 7.5 + 5 = 12.5
Upstream trip took hour many more hours than the downstream trip = 7.5 - 5 = 2.5

IMO D
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GOHOSATRAJIT
A boat traveled 90 miles upstream at a constant speed and then traveled the same distance downstream at a constant speed. If the constant velocity of the water is 3 miles per hour and the whole trip took 12.5 hours, the upstream trip took hour many more hours than the downstream trip?

(A) 1
(B) 1.5
(C) 2
(D) 2.5
(E) 3

The constant velocity of the water is 3 miles per hour.
Since the current INCREASES the downstream speed by 3 mph and DECREASES the upstream speed by 3 mph, the DIFFERENCE between the two speeds = 6 mph.

The whole trip took 12.5 hours.
Let U = the upstream time and D = the downstream time.
Since the trip took a total time of 12.5 hours, we get:
U+D = 12.5

The upstream trip took how many more hours than the downstream trip?
We can PLUG IN THE ANSWERS, which represent the value of U-D.
When the correct answer is plugged in, the difference between the two speeds = 6.

D: U-D = 2.5
Adding together U+D = 12.5 and U-D = 2.5, we get:
2U = 15
U=7.5, implying that D=5
Downstream speed - upstream speed \(= \frac{90}{5} - \frac{90}{7.5} = 18 - 12 = 6\)
Success!

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let speed of boat = v.
90/(v-3) + 90/(v+3) = 12.5
On solving we get v = 15

So, to find the diff in time:
90/18 - 90/12
=2.5
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