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garcmillan
If n is the smallest integer such that 216 times n is the square of an integer, what is the value of n?

(A) 1
(B) 2
(C) 6
(D) 12
(E) 24

For any integer to be a square of any other number or multiples of any numbers, the corresponding number/multiples should have exponents in even numbers.

(216)*(n) = square of an INT

The above expression simply means the prime factorization of the product of 216 and n should have even exponents.

Now lets break down the given expression,

216 = (\(2^3\))*(\(3^3\))*(n)

i.e, n should have AT LEAST one 2 and one 3 for the product to have even exponents.

Therefore, the minimum value n can have is 2*3 = 6.

The answer is C
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garcmillan
If n is the smallest integer such that 216 times n is the square of an integer, what is the value of n?

(A) 1
(B) 2
(C) 6
(D) 12
(E) 24

Given: n is the smallest integer such that 216 times n is the square of an integer.

Asked: What is the value of n?

\(216 = 6^3 = 2^3*3^3\)
n = 2*3 = 6 will make it a perfect square of an integer

IMO C
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