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shridhar786
What is the value of \(\frac{1}{5*6}\) + \(\frac{2}{6*8}\)+ \(\frac{3}{8*11}\) + \(\frac{4}{11*15}\)?

\(\frac{1}{5*6}\) + \(\frac{2}{6*8}\)+ \(\frac{3}{8*11}\) + \(\frac{4}{11*15}\) can be written as

= \(\frac{1}{5}\) - \(\frac{1}{6}\) + \(\frac{1}{6}\) - \(\frac{1}{8}\)+ \(\frac{1}{8}\) - \(\frac{1}{11}\) +\(\frac{1}{11}\) - \(\frac{1}{15}\)

= \(\frac{1}{5}\) - \(\frac{1}{15}\)

= \(\frac{2}{15}\)

D is the answer
can u explain how it can be expanded (re written) like that?
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shridhar786
What is the value of \(\frac{1}{5*6}\) + \(\frac{2}{6*8}\)+ \(\frac{3}{8*11}\) + \(\frac{4}{11*15}\)?

\(\frac{1}{5*6}\) + \(\frac{2}{6*8}\)+ \(\frac{3}{8*11}\) + \(\frac{4}{11*15}\) can be written as

= \(\frac{1}{5}\) - \(\frac{1}{6}\) + \(\frac{1}{6}\) - \(\frac{1}{8}\)+ \(\frac{1}{8}\) - \(\frac{1}{11}\) +\(\frac{1}{11}\) - \(\frac{1}{15}\)

= \(\frac{1}{5}\) - \(\frac{1}{15}\)

= \(\frac{2}{15}\)

D is the answer
can u explain how it can be expanded (re written) like that?


\(\frac{1}{5}\) - \(\frac{1}{6}\) = \(\frac{6-5}{5*6}\)= \(\frac{1}{5*6}\)

\(\frac{1}{6}\) - \(\frac{1}{8}\) = \(\frac{8-6}{8*6}\) = \(\frac{2}{6*8}\)

\(\frac{1}{8}\) - \(\frac{1}{11}\) = \(\frac{11-8}{8*11}\) =\(\frac{3}{8*11}\)

\(\frac{1}{11}\) - \(\frac{1}{15}\) = \(\frac{15-11}{11*15}\) = \(\frac{4}{11*15}\)

got it
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=>

Remember the following properties.
1/n(n+1) = 1/n – 1/(n+1).
2/n(n+2) = 1/n – 1/(n+2).
3/n(n+3) = 1/n – 1/(n+3).
4/n(n+4) = 1/n – 1/(n+4).

Then we have
1/(5*6) + 2/(6*8) + 3/(8*11) + 4/(11*15)
= (1/5-1/6)+(1/6-1/8)+(1/8-1/11)+(1/11-1/15)
= 1/5 – 1/15
= 2/15

Therefore, D is the answer.
Answer: D
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