Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 1808:00 PM PDT
-09:00 PM PDT
Video explanations + diagnosis of 10 weakest areas + 150+ short videos + study plan!
Sep 2107:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
13 Oct 2019, 08:24
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
63% (03:04) correct
38%
(02:50)
wrong
based on 64
sessions
History
Date
Time
Result
Not Attempted Yet
Find the area of the shaded region if ABCD is a square of side 4 units and E is the midpoint of side BC.
A. 2
B. 8/3
C. 4
D. 16/3
E. None of these
A. 2
B. 8/3
C. 4
D. 16/3
E. None of these
Attachments
1.png [ 10.79 KiB | Viewed 3128 times ]
13 Oct 2019, 08:39
Kudos
Bookmarks
Dillesh4096
\(\triangle {CFE}\) and \(\triangle {DFA}\) are similar so when we draw an altitude passing through F, the height or altitude of both triangles will be in ratio 2/4 or 1/2.
Thus if smaller altitude is x, bigger altitude = 2x and \(x+2x=4..x=\frac{4}{3}\)
Area of ABED = \(\frac{4+2}{2}*4=12\)=area of shaded region \(+4+\frac{16}{3}\)..
area of shaded region =\(12-\frac{28}{3}=\frac{36-28}{3}=8/3\)
B
Attachments
1.png [ 18.36 KiB | Viewed 3050 times ]
13 Oct 2019, 09:39
Kudos
Bookmarks
Dillesh4096
Let the coordinates of point A be (0,0)
Coordinates of point E = (4,2)
Equation of line AC : y = x
Equation of line DE passing through (0,4) & (4,2): y-4 = (-2/4)x: y = 4 - x/2
Coordinates of point F (intersection point of AC & DE)
y = x = 4 - x/2
x = 8/3 = y
Coordinates of point F = (8/3,8/3)
Using discriminant method,
Area of triangle AFE = 1/2 (32/3 - 16/3) = 8/3
IMO B
