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chetan2u
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In a rectangle , the length of the diagonal is 8 meters and the length of the perpendicular drawn on that diagonal from the opposite corner is 4 meters. What is the area of the rectangle in sq meters ?

A)32
B)16
C)24
D)12
E)64


Area of a rectangle = length * breadth when one of these is taken as the base
OR
Area = 2*(1/2*Diagonal*(perpendicular on this diagonal from the opposite vertex))=2*8*4*(1/2)=33


A

chetan2u , you made calulation mistake.. answer is 32. You written as 33. Which is not in options.

Regards,
Rajat

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chetan2u
KSBGC
In a rectangle , the length of the diagonal is 8 meters and the length of the perpendicular drawn on that diagonal from the opposite corner is 4 meters. What is the area of the rectangle in sq meters ?

A)32
B)16
C)24
D)12
E)64


Area of a rectangle = length * breadth when one of these is taken as the base
OR
Area = 2*(1/2*Diagonal*(perpendicular on this diagonal from the opposite vertex))=2*8*4*(1/2)=33

A

sir typing error ho gaya
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rajatchopra1994
Area of Retangle= 2 × [1/2 x diagonal*(perpendicular on this diagonal)]
=2x8x4x(1/2)
=32

Answer is A

Please give kudos, if you find my explanation good enough

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Sir, is this a formula? Why is it so different?
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ShahadatHJ
rajatchopra1994
Area of Retangle= 2 × [1/2 x diagonal*(perpendicular on this diagonal)]
=2x8x4x(1/2)
=32

Answer is A

Please give kudos, if you find my explanation good enough

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Sir, is this a formula? Why is it so different?
Hi ShahadatHJ, the formula above is for two triangles. It's the easiest way to solve, because the problem gives you the base and height for 2 congruent triangles. We can think of the diagonal as the base, and the "perpendicular drawn on that diagonal" as the height.
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ShahadatHJ
rajatchopra1994
Area of Retangle= 2 × [1/2 x diagonal*(perpendicular on this diagonal)]
=2x8x4x(1/2)
=32

Answer is A

Please give kudos, if you find my explanation good enough

Posted from my mobile device
Sir, is this a formula? Why is it so different?
Hi ShahadatHJ, the formula above is for two triangles. It's the easiest way to solve, because the problem gives you the base and height for 2 congruent triangles. We can think of the diagonal as the base, and the "perpendicular drawn on that diagonal" as the height.
Now, it makes sense, thank you very much. It was itching me for a while. :)
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When a diagonal is drawn in a rectangle it forms a 45-45-90 triangle in the ratio x:x:root2X. We are given the length of the diagonal as 8, this is the length of the side opposite to 90 degreee, equate it to root2X. We find x =4root2.
Therefore are of rectangle =(4root2)^2 =32
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