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27 Nov 2019, 01:47
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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54% (02:25) correct
46%
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wrong
based on 222
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Alicia purchases three different rings that can each be worn on any of her fingers, excluding her thumbs. If she wants to wear at least one ring on each hand, with no more than one ring per finger, how many different ways can she distribute the rings among her eight fingers?
A. 192
B. 288
C. 336
D. 415
E. 465
Are You Up For the Challenge: 700 Level Questions
A. 192
B. 288
C. 336
D. 415
E. 465
Are You Up For the Challenge: 700 Level Questions
27 Nov 2019, 06:17
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Bunuel
Two ways.
(I) As also shown above
Choose 2 fingers on one hand and one finger on second hand =2*4C2*4C1=2*4*4*3/2=48...multiplication by 2 is because we can choose any hand for 2 fingers
Now these rings can be arranged in 3! Or 6 ways
Total = 48*6=288
(II) Total ways =8*7*6 ( first finger any of 8 fingers and so on)
Restricted ways = All three on same hand = 4*3*2*(2)
Total ways =8*7*6-4*3*2*2=336-48=288
B
General Discussion
27 Nov 2019, 05:26
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Choose 2 fingers of left hand and one finger of the right one or vice-versa. Total number of possible arrangements of 3 different rings = 3!
Total number of ways
= 2*4C2*4C1*3!
= 288
Total number of ways
= 2*4C2*4C1*3!
= 288
Bunuel
