(1st) we can drawn in only 2 of the identical semicircles with diameter = 2. Have these be vertically opposite from each other.
The two semicircles will intersect in the center of the square and the point of Tangency will be the exact center of the Square (b/c vertically opposite each other)
The area OUTSIDE these 2 vertically opposite semicircles will be TWO of the “triangular like” white areas outside the bounds of the 2 semicircles but inside the square.
this means: (Area of Square) - (Area of 2 semicircles) = (2 of the white triangular-like” Areas inside the Square)
2 identical semi circles with diameter = 2 (r = 1) is the same as ONE Whole Circle with radius = 1
(2)^2 - (1)^2 (pi) = area of 2 of the white triangular-like sections inside the Square =
(4 - (pi))
(2nd)To get the Area of ALL FOUR of these white triangular sections, we need to double the area for TWO we found above:
(2) * (4 - (pi)) = Area of White “triangular-like” sections inside the square
(3rd) to find the area of the shaded portions covered, we need to subtract the above Area from the entire Area of the Square and then take 95% of that value
95% * [ (2)^2 - (2) * (4 - (pi)) ]
We can estimate (pi) at around ~ 3.1
95% * [ (4) - (2) * (4 - 3.1) ]
95% * [ (4) - (2) * (.9) ]
95% * [ 2.2 ]
Since we have underestimated the value of (pi) ——-> the value of 2.2 will be slightly overvalued.
(C) 2.2 is the approximate value
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