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Bunuel
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(1st) we can drawn in only 2 of the identical semicircles with diameter = 2. Have these be vertically opposite from each other.

The two semicircles will intersect in the center of the square and the point of Tangency will be the exact center of the Square (b/c vertically opposite each other)

The area OUTSIDE these 2 vertically opposite semicircles will be TWO of the “triangular like” white areas outside the bounds of the 2 semicircles but inside the square.

this means: (Area of Square) - (Area of 2 semicircles) = (2 of the white triangular-like” Areas inside the Square)

2 identical semi circles with diameter = 2 (r = 1) is the same as ONE Whole Circle with radius = 1

(2)^2 - (1)^2 (pi) = area of 2 of the white triangular-like sections inside the Square =

(4 - (pi))



(2nd)To get the Area of ALL FOUR of these white triangular sections, we need to double the area for TWO we found above:

(2) * (4 - (pi)) = Area of White “triangular-like” sections inside the square

(3rd) to find the area of the shaded portions covered, we need to subtract the above Area from the entire Area of the Square and then take 95% of that value

95% * [ (2)^2 - (2) * (4 - (pi)) ]

We can estimate (pi) at around ~ 3.1

95% * [ (4) - (2) * (4 - 3.1) ]

95% * [ (4) - (2) * (.9) ]

95% * [ 2.2 ]

Since we have underestimated the value of (pi) ——-> the value of 2.2 will be slightly overvalued.


(C) 2.2 is the approximate value

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Solution:

The approach is simple.

Area of shaded region = Area if 4 semi circles - Area of square.

When we calculate the area of the 4 semi-circles, we calculate the shaded region twice and the unshaded region once.

Now if you look close, this extra area (1 part of shaded + 1 part of unshaded) is nothing but area of the square.

So, Area of shaded region \(= 4\times \frac{\pi \times 1^2}{2} - (2\times 2)\)

We know radius os semicircle \(= 1\) and its area \(= \frac{\pi \times radius^2}{2}\)

\(⇒ 2\pi-4\)

\(⇒ 2\times \frac{22}{7} - 4\)

\(⇒ 2.2 \)

Hence the right answer is Option C.
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Find the area of one small piece and multiply by 8 to get the shaded area and then 95% to get the area

8*(Area of sector - Area of triangle)*95% = 8*(Pi/4-1/2)*95% = (2Pi-4)*95% = approx 2.2
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