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{5, 8, 3, 7}
How many different numbers k are there such that the sum of k and 3 of the 4 numbers shown equals 24?

A. 4
B. 5
C. 6
D. 8
E. Infinitely many

Can anyone please explain the question

Posted from my mobile device

There are 4C3 = 4 different triplets that can be formed from the set {5, 8, 3, 7}. Each triplet of numbers gives a different sum:

    5 + 8 + 3 = 16
    5 + 8 + 7 = 20
    5 + 3 + 7 = 15
    8 + 3 + 7 = 18

Therefore, for each triplet there exists a k such that adding it to the triplet will total 24.

Answer: A.
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Can anyone please explain the question

Posted from my mobile device


{5, 8, 3, 7}

How many different numbers k are there such that the sum of k and 3 of the 4 numbers shown equals 24?

A. 4

B. 5

C. 6

D. 8

E. Infinitely many

Question is simple if you understand the convoluted language.
It basically asks for possible count of numbers which when added to the 3 out of 4 numbers(i.e. 5, 8, 3, 7) gives a sum of 24.
Eventually we are adding 4 numbers that sum to 24. So, how many possibilities the answer we are looking for.

Therefore either by counting the possibilities of 3 numbers from these 4 numbers or by using combination formula we can find our answer.
Since it is about sum the position of the digits is not a concerned. Let's count
- With 5 we have 8,3 and 8,7. So, 2 possibilities
- With 8 we have 3,7. So, only 1 possibility
- With 3 we have 7,5. So, only 1 possibility

Total 4 possibilites.
Rest possibilities are repeats. Thus, only 4 different values of k possibile.

Answer A.
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