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12 Dec 2019, 02:13
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
76% (01:11) correct
24%
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based on 120
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If n is a positive odd integer and \(k = n^3 + 2n\), what is the value of \((−1)^k − (−1)^{k+1}\)?
A. −2
B. −1
C. 0
D. 1
E. 2
A. −2
B. −1
C. 0
D. 1
E. 2
12 Dec 2019, 04:07
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Bunuel
\(k = n^3 + 2n=n(n^2+2)=Odd*Odd=Odd\), so k is odd.
\((−1)^k − (−1)^{k+1}\)=\((-1)^{odd}-(-1)^{odd+1)=-1-(1)=-2\)
A
12 Dec 2019, 05:49
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If n is a positive odd integer and \(k = n^3 + 2n\), what is the value of \((−1)^k − (−1)^{k+1}\)?
A. −2 --> correct
solution: n is odd,
\(k = n^3 + 2n\)
' = \( (odd)^3 + 2*(odd) \)
' = odd + even=odd
\((−1)^k − (−1)^{k+1}\)
= \( (-1)^{odd} - (-1)^{odd+1}\)
= -1 - (+1)
= -2
B. −1
C. 0
D. 1
E. 2
A. −2 --> correct
solution: n is odd,
\(k = n^3 + 2n\)
' = \( (odd)^3 + 2*(odd) \)
' = odd + even=odd
\((−1)^k − (−1)^{k+1}\)
= \( (-1)^{odd} - (-1)^{odd+1}\)
= -1 - (+1)
= -2
B. −1
C. 0
D. 1
E. 2
