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Bunuel
A car travels the first one-third of the total time taken to cover a distance at a speed of 10 kmph, the next one-third of time at a speed of 20 kmph and the last one-third time at 60 kmph. Find the average speed of the car for the whole journey.

A. 18 kmph
B. 20 kmph
C. 25 kmph
D. 30 kmph
E. 40 kmph


Let the total time taken be 3x..
Distance traveled in first x hr is speed*time =10*x or 10x. Similarly next x hrs 20x and 60x.
Total distance covered =10x+20x+60x=90x
Time taken =3x
Average speed =90x/3x=30kmph

D

OA corrected from A to D
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A car travels the first one-third of the total time taken to cover a distance at a speed of 10 kmph, the next one-third of time at a speed of 20 kmph and the last one-third time at 60 kmph. Find the average speed of the car for the whole journey.

Average speed = Total Distance / Total Time

Let total time be "T"

Therefore, total distance D = 10x(T/3) + 20x(T/3)+ 60x(T/3) = 30T

Average speed = Total Distance / Total Time = 30T/T = 30 kmph

Hence D
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Bunuel
A car travels the first one-third of the total time taken to cover a distance at a speed of 10 kmph, the next one-third of time at a speed of 20 kmph and the last one-third time at 60 kmph. Find the average speed of the car for the whole journey.

A. 18 kmph
B. 20 kmph
C. 25 kmph
D. 30 kmph
E. 40 kmph


When an object travels at different speeds, its average speed is the weighted average of all individual speeds with 'time taken at each speed' as the weights. Here since equal time was taken at speeds of 10, 20 and 60, the average speed will simply be the average of all 3 speeds i.e.

Average speed =\( \frac{(10 + 20 + 60)}{3} = 30\) kmph

To read up on what are the weights in weighted averages, check: https://anaprep.com/arithmetic-weights- ... d-average/
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