The ratio of the present ages of a father and a son is 8 : 1. Eight ye

Question

The ratio of the present ages of a father and a son is 8 : 1. Eight years from now, the ratio would be 10 : 3. What is the present age of the father?

A. 24
B. 32
C. 40
D. 48
E. 56

Archit3110 · Answer

given
f/s= 8/1
after 8 years
f+8/s+8 = 10/3
solve for f
we get f= 32
IMO B

IanStewart · Answer

If in 8 years, the ratio of the father's age to the son's age will be 10 to 3, then when we add 8 to the father's age, we must get a multiple of 10. Among the answer choices, only answer B gives us a multiple of 10 when we add 8 to it, so B must be right.

Abhishek009 · Answer

\frac{F}{S} = \frac{8}{1} 
 \frac{F_8}{S_8} = \frac{10}{3}

Now, check carefully

\frac{F}{S} = \frac{8------+2------>10}{1-------+2------>3}

2 is represented as 8
1 is represented as 4
 So, Present age of father will be 4*8 = 32, Answer must be (B)

BadukMagician · Answer

F/s = 8/1

F+8 / S+8 = 10/3

3f+24 = 10s+80

3f = 10s+56

f = (10s + 56) / 3

return to original ratio

((10s + 56) / 3) / s = 8 / 1

(10s + 56) / 3s = 8/1

10s + 56 = 24s

56 = 14s

4=S

F/4 = 8/1

F=32 Answer choice B

The ratio of the present ages of a father and a son is 8 : 1. Eight ye

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The ratio of the present ages of a father and a son is 8 : 1. Eight ye

Prep Toolkit

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