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shameekv1989
i follow x will always be Odd but may I know when would E be not true? It is the given condition after all.

There was a typo. E reads: \(a^2 - b^2 = x\). Edited. Thank you.
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SajjadAhmad
If a is even, b is odd, and \(a^2 + b^2 = x\) which of following must be true?

A. x is the square of an integer.

B. x is odd.

C. x is a multiple of a. x

D. is prime

E. \(a^2 - b^2 = x\)

Since a is even and b is odd, then a^2 is even and b^2 is odd. Because the sum of an even integer and an odd integer is odd, then x must be odd.

Answer: B
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If a is even, b is odd, and \(a^2 + b^2 = x\) which of following must be true?

A. x is the square of an integer.

B. x is odd. --> correct: \(x= a^2 + b^2 = even*even + odd*odd = even + odd = odd\)

C. x is a multiple of a. x

D. is prime

E. \(a^2 - b^2 = x\)
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SajjadAhmad
If a is even, b is odd, and \(a^2 + b^2 = x\) which of following must be true?

A. x is the square of an integer.

B. x is odd.

C. x is a multiple of a. x

D. is prime

E. \(a^2 - b^2 = x\)

\(a^2 + b^2 = x\)
a^2 is even & b^2 is odd
a^2 + b^2 = even + odd = odd

IMO B
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