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Bunuel
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IMO answer is E
Unfortunately I can’t show the process it’s all under a big sqrt(within sqrt())

Posted from my mobile device
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↧↧↧ Detailed Video Solution to the Problem ↧↧↧



\(a* = \frac{1}{\sqrt{a^3}}\) and we need to find the value of \((2^{-\frac{1}{4*}})*\)

\(a* = \frac{1}{\sqrt{a^3}}\) = \(1/a^{3/2}\) = \(a^{-3/2}\)


Lets start by finding the value of 4*

=> We need to substitute a with 4 in \(a* = a^{-3/2}\) to get the value of 4*

\(4* = 4^{(-3/2)}\) = (2^2)^(-3/2) = 2^(2*-3/2) = 2^-3

=> \((2^{-\frac{1}{4*}})*\) = \((2^{-\frac{1}{2^{-3}}})*\) = \((2^{-2^3})*\) = \((2^{-8})*\)

\((2^{-8})* = (2^{-8})^{(-3/2)}\) = \(2^{12}\)


So, Answer will be E
Hope it helps!

Watch the following video to MASTER Functions and Custom Characters

­
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