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19 Jun 2020, 04:07
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Three identical circles are drawn in a rectangle as shown above. If the radius of each circle is 1, what is the area of the rectangle?
A. \(8+\sqrt{3}\)
B. \(8+2\sqrt{3}\)
C. \(8+3\sqrt{3}\)
D. \(8+4\sqrt{3}\)
E. \(8+5\sqrt{3}\)
Are You Up For the Challenge: 700 Level Questions
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19 Jun 2020, 04:29
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B = AD +1+1
\(AD = \sqrt{2^2-1^2}\) = √3
B =√3+2
L*B = 4*(√3+2) = 4√3+8
General Discussion
yashikaaggarwal
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19 Jun 2020, 04:17
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Connect radius of circles,
Resulting an equilateral triangle of side 2
The height of equilateral triangle = (Side/2)*√3
Height = 2/2*√3
Height = √3
Height or breadth of rectangle= height of equilateral+2*radius.
=> 2+√3
Length of rectangle = 4*radius
=> 4*1 => 4
Area of rectangle = 4*(2+√3)
=> 8+4√3
Answer is D
Posted from my mobile device
Resulting an equilateral triangle of side 2
The height of equilateral triangle = (Side/2)*√3
Height = 2/2*√3
Height = √3
Height or breadth of rectangle= height of equilateral+2*radius.
=> 2+√3
Length of rectangle = 4*radius
=> 4*1 => 4
Area of rectangle = 4*(2+√3)
=> 8+4√3
Answer is D
Posted from my mobile device
