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01 Jul 2020, 10:39
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
69% (01:18) correct
31%
(01:45)
wrong
based on 157
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\(12x + 3 – (4 − 4x)\)
If the expression above is equal to an integer, which of the following CANNOT be a possible value for x ?
I. \(- \frac{4}{3}\)
II. \(\frac{3}{4}\)
III. \(\frac{4}{3}\)
A. I only
B. II only
C. I and II only
D. I and III only
E. I, II, and III
If the expression above is equal to an integer, which of the following CANNOT be a possible value for x ?
I. \(- \frac{4}{3}\)
II. \(\frac{3}{4}\)
III. \(\frac{4}{3}\)
A. I only
B. II only
C. I and II only
D. I and III only
E. I, II, and III
01 Jul 2020, 10:51
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Explanation:
12x+3–(4−4x)
1. x= −4/3
12(-4/3) + 3 -(4+4x4/3)
-67/3
II. 3/4
12(3/4) + 3 -(4-4x3/4)
11
III. 4/3
12(4/3) + 3 -(4-4x4/3)
61/3
IMO-B
12x+3–(4−4x)
1. x= −4/3
12(-4/3) + 3 -(4+4x4/3)
-67/3
II. 3/4
12(3/4) + 3 -(4-4x3/4)
11
III. 4/3
12(4/3) + 3 -(4-4x4/3)
61/3
IMO-B
01 Jul 2020, 10:52
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Bunuel
Simplifying the expression gives \(12x + 4x + 3 - 4 = 16x - 1\). For this expression to be an integer, we need \(16x\) to be an integer.
If we let x equal to I or III, multiplying the value by 16 will not cancel the 3 in the denominator so I and III will not satisfy but II's denominator can be canceled by multiplying 16 so II only satisfies.
Ans: B
