Last visit was: 26 Apr 2026, 19:01 It is currently 26 Apr 2026, 19:01
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
RafZaf
User avatar
Current Student
Joined: 27 Apr 2020
Last visit: 12 Sep 2023
Posts: 70
Own Kudos:
24
 [8]
Given Kudos: 111
GMAT 1: 710 Q45 V44
GMAT 1: 710 Q45 V44
Posts: 70
Kudos: 24
 [8]
Kudos
Add Kudos
8
Bookmarks
Bookmark this Post
User avatar
Duuperman
Joined: 11 May 2020
Last visit: 23 May 2022
Posts: 1
Own Kudos:
Given Kudos: 6
Location: Bangladesh
Concentration: Finance, International Business
GMAT 1: 730 Q50 V40
GPA: 2.99
GMAT 1: 730 Q50 V40
Posts: 1
Kudos: 1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
IanStewart
User avatar
GMAT Tutor
Joined: 24 Jun 2008
Last visit: 24 Apr 2026
Posts: 4,143
Own Kudos:
11,280
 [3]
Given Kudos: 99
Expert
Expert reply
Posts: 4,143
Kudos: 11,280
 [3]
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
avatar
fmcgee1
Joined: 22 Jun 2020
Last visit: 31 May 2024
Posts: 56
Own Kudos:
Given Kudos: 31
GMAT 1: 700 Q47 V40
GMAT 1: 700 Q47 V40
Posts: 56
Kudos: 31
Kudos
Add Kudos
Bookmarks
Bookmark this Post
IanStewart
You could use the three dimensional version of the Pythagorean Theorem: if a, b, and c are three mutually perpendicular lengths between two points in 3-dimensions (so for example, if they are the length, width, and height of a box), the straight line distance d between those points is given by

d^2 = a^2 + b^2 + c^2

Or you can use the ordinary Pythagorean Theorem twice. The base of our box measures 12 by 16, so the diagonal along the base is 20 (since this is just four times as big as a 3-4-5 triangle). So we can now make a right triangle using the diagonal along the base and the height of the box. We have a base diagonal of 20, and a height of 20, so our triangle is an isosceles right (45-45-90) triangle, and the hypotenuse is √2 times either side, so is 20√2.

Can I ask, how do we know what the base is? Like if I use the base as 12 x 16, and the height as 20, I will get a different answer than if I use the base as 20 x 12 and the height as 16.
User avatar
IanStewart
User avatar
GMAT Tutor
Joined: 24 Jun 2008
Last visit: 24 Apr 2026
Posts: 4,143
Own Kudos:
Given Kudos: 99
Expert
Expert reply
Posts: 4,143
Kudos: 11,280
Kudos
Add Kudos
Bookmarks
Bookmark this Post
fmcgee1

Can I ask, how do we know what the base is? Like if I use the base as 12 x 16, and the height as 20, I will get a different answer than if I use the base as 20 x 12 and the height as 16.

It truly doesn't matter - I used 12 by 16 as the base because it was the easiest set of numbers to work with, but you'll get the same answer no matter how you orient the box.
avatar
billionaire999
Joined: 26 Mar 2021
Last visit: 12 May 2021
Posts: 39
Own Kudos:
17
 [3]
Given Kudos: 24
Location: India
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
RafZaf
Rich is shipping a galvanized steel rod of negligible width in a rectangular container that measures 12 feet by 16 feet by 20 feet. What is the length, in feet, of the largest rod that he can fit in the container ?

(A) \(10\sqrt{2}\)
(B) 20
(C) 30
(D)\( 20\sqrt{2}\)
(E) \(30\sqrt{2}\)

Diagonal of a rectangular box = \sqrt{H^2 + B^2 + L^2 }

= \sqrt{12x12 + 16x16 + 20x20 }
=\sqrt{800}
=20\sqrt{2}

Hope it helps all
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,992
Own Kudos:
Posts: 38,992
Kudos: 1,118
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109910 posts
Tuck School Moderator
852 posts