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15 Sep 2020, 05:45
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D
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Difficulty:
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Question Stats:
96% (01:05) correct
4%
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wrong
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A wire that weighs 24 kilograms is cut into two pieces so that one of the pieces weighs 16 kilograms and is 34 meters long. If the weight of each piece is proportional to its length, how many meters long is the other piece of wire?
A. 8
B. 11
C. 13
D. 17
E. 20
A. 8
B. 11
C. 13
D. 17
E. 20
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Archit3110
Major Poster
Updated on: 15 Sep 2020, 05:52
Originally posted by Archit3110 on 15 Sep 2020, 05:49.
Last edited by Archit3110 on 15 Sep 2020, 05:52, edited 1 time in total.
Last edited by Archit3110 on 15 Sep 2020, 05:52, edited 1 time in total.
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Bunuel
given A+B = 24
B = 8 and A = 16
also given weight = k * length ; k = weight /length
we get
K= 16/34
so for 8 kgs it would be
8 = k * length
8* 34/16 = length 17 mtrs
OPTION D
15 Sep 2020, 05:51
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1 piece of the wire weighs 16 kgs. So, the other piece will weigh 24-16 = 8 kgs.
The 16 kgs wire is 34m long, and the weight of each piece is proportional to its length.
So, let the length of the other piece of wire be x.
16/34 = 8/x
x = (8*34)/16
x = 17.
The answer will be D.
The 16 kgs wire is 34m long, and the weight of each piece is proportional to its length.
So, let the length of the other piece of wire be x.
16/34 = 8/x
x = (8*34)/16
x = 17.
The answer will be D.
