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May 0312:30 AM EDT
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Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
21 Sep 2020, 04:00
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B
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Difficulty:
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56% (01:52) correct
44%
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wrong
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In a class, 60% of students play soccer or basketball. If 10% play both sports and 60% do not play soccer, what is the probability that a student chosen at random from the class plays basketball only?
A. 0.1
B. 0.2
C. 0.3
D. 0.4
E. 0.5
A. 0.1
B. 0.2
C. 0.3
D. 0.4
E. 0.5
yashikaaggarwal
Senior Moderator - Masters Forum
Joined: 19 Jan 2020
Last visit: 29 Mar 2026
Posts: 3,088
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Location: India
Schools: Cranfield (A) Warwick MiM "23 (M)
GPA: 4
WE:Analyst (Internet and New Media)
21 Sep 2020, 05:39
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Let Total no. of students = 100
the probability that a student chosen at random from the class plays basketball only = Students playing only Basketball/ total no. of students = 20/100 = 0.2
Answer is B
the probability that a student chosen at random from the class plays basketball only = Students playing only Basketball/ total no. of students = 20/100 = 0.2
Answer is B
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11 Oct 2020, 03:38
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Let the total number of students be 100.
P(students who do no play soccer)= 60
P(students who play soccer)= 100-60=40
P(students who only play soccer)= P(students who play soccer)- P(students who play both)=40-10=30
P(students who play soccer or basketball)=P(only soccer) + P(only basketball) +P(students who play both)
60=30 + P(only basketball) + 10
P(only basketball)= 60-40=20% = 0.2
P(students who do no play soccer)= 60
P(students who play soccer)= 100-60=40
P(students who only play soccer)= P(students who play soccer)- P(students who play both)=40-10=30
P(students who play soccer or basketball)=P(only soccer) + P(only basketball) +P(students who play both)
60=30 + P(only basketball) + 10
P(only basketball)= 60-40=20% = 0.2
