After x% of their games had been played, the Lions had won 40% of thei

Question

After x% of their games had been played, the Lions had won 40% of their games. In terms of x, which of the following expresses the minimum percentage of games the lions could have won at the end of the season?

A. 60x%

B. 40x%

C. \([60\frac{x}{100}]\)%

D. \([40\frac{x}{100}]\)%

E. \([20\frac{x}{100}]\)%

A. 60x%
 
B. 40x%
 
C.    %
 
D.    %
 
E.    %

prateekchugh · Answer

After x% of their games had been played, the Lions had won 40% of their games. In terms of x, which of the following expresses the minimum percentage of games the lions could have won at the end of the season?

A. 60x%

B. 40x%

C. \([60\frac{x}{100}]\)%

D. \([40\frac{x}{100}]\)%

E. \([20\frac{x}{100}]\)%

Let the total game played = y

x% of their games had been played= \frac{ x}{100} * y

the Lions had won 40% of their games=  \frac{40}{100} * \frac{ x}{100} * y

Let suppose the lions looses all its remaining games,

the minimum percentage of games the lions could have won at the end of the season=  \frac{Total winning}{ Total games} * 100 
 =  \frac{40 * x * y}{10000} / y * 100 
=  \frac{40*x}{100}  %

Answer is D

IanStewart · Answer

prateekchugh gives a perfect algebraic solution above. You could also notice that when x = 100, the answer to the question must be exactly 40%. Only answer D can possibly be right.

Target4bschool · Answer

Let total games = y games. 
Now, games played =  \frac{x}{100} * y  
Lions won  \frac{40}{100} * \frac{x}{100} * y  games

Now, min. number of games Lions could have won =  \frac{40}{100} * \frac{x}{100} * y

As we are finding the min. number, we can divide the above by y because number of games (y) can't be a fraction. It will be a natural number.

So, answer is D ->  \frac{40}{100} * \frac{x}{100}

sameerm22 · Answer

Let's say:
Total games = 100
Played so far: 60 (some easy number)
Now they have won 40%, so in our case Won = 0.4*60 = 24.

Substitute x=60 in the answer choices... only D gives Won = 24... which matches with our assumption.

Basshead · Answer

Quick approach is to let x = 100, or all of the games played.

If they won 40% of ALL their games played, then they won:

D.    %

=  \frac{40}{100} %

handbalancer · Answer

Bunuel  can you please help with a solution for this

ScottTargetTestPrep · Answer

Solution:

If n = the number of games in the whole season, then the Lions had won:

40/100 * (x/100 * n) = (40x/100)/100 * n games

That is, they had won at least 40x/100 percent of the games in the season.

Answer: D

LeopardLiu · Answer

After x% of their games had been played, the Lions had won 40% of their games. In terms of x, which of the following expresses the minimum percentage of games the lions could have won at the end of the season?

A. 60x%

B. 40x%

C. \([60\frac{x}{100}]\)%

D. \([40\frac{x}{100}]\)%

E. \([20\frac{x}{100}]\)%

It's a trick one. But if we understand the intended meaning, we could get our answer in a second. The minimum percentage after winning 40 % of the game after x% of the game. Notice that if Lions will never win in the later game, Lions has his minimum percentage winning of the game, percentage he obtained in the first x% part of the game but under the whole game scale.

After x% of their games had been played, the Lions had won 40% of thei

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After x% of their games had been played, the Lions had won 40% of thei

Prep Toolkit

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My Rewards