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The prompt is wrong, isn't it? Answer should express Y in terms of X and not X in terms of Y, or am I mistaken?
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chrtpmdr
The prompt is wrong, isn't it? Answer should express Y in terms of X and not X in terms of Y, or am I mistaken?
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Yes. Edited. Thank you.
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Vvin how did you go from x = 2^4y / 2^3 to x= 2^4y * 2^-3?
Dont the exponents 4y just minus 3?
I dont quite follow but i believe im missing something.

*edit
is it because exponent 4y cannot minus 3 thus it would be 2^4y-3


thanks
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\(8x = 16^y\)

=> x = \(\frac{16^y }{ 8}\)

=> x = \(\frac{(2^4)^y }{ (2^3)}\)

=> x = \(\frac{(2^{4y})}{ (2^3)}\)

=> x = \((2^{4y -3})\)

Answer E
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sjuniv32
If 8x = \(16^y\), what is x in terms of y?


(A) \(2^y\)

(B) \(2^ {2y - 3}\)

(C) \(2^ {3y - 4}\)

(D) \(2^ {4y - 2}\)

(E) \(2^ {4y – 3}\)

\(2^3*x = 2^{4y}\)

So, \(x = 2^{4y - 3}\), Answer is clearly (E)
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Russ19
If 8x = \(16^y\), what is x in terms of y?


(A) \(2^y\)

(B) \(2^ {2y - 3}\)

(C) \(2^ {3y - 4}\)

(D) \(2^ {4y - 2}\)

(E) \(2^ {4y – 3}\)
\(8x = 16^y\)

Or, \(2^3*x = 2^{4y}\)

Or, \(x = 2^{4y-3}\), Answer will be (E)
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